If you increase solute moles while solvent moles remain fixed, which statement about the solvent mole fraction is true?

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Multiple Choice

If you increase solute moles while solvent moles remain fixed, which statement about the solvent mole fraction is true?

Explanation:
Mole fraction is the ratio of moles of a component to the total moles in the mixture. If the solvent moles stay fixed and you add more solute, the total number of moles increases, but the solvent moles do not. So the fraction that represents the solvent shrinks. Mathematically, X_solvent = n_solvent / (n_solvent + n_solute). With n_solvent fixed and n_solute increasing, the denominator grows while the numerator stays the same, hence X_solvent decreases. For intuition, adding more solute increases the total particle count, making the solvent occupy a smaller share of the mixture. So the solvent mole fraction decreases.

Mole fraction is the ratio of moles of a component to the total moles in the mixture. If the solvent moles stay fixed and you add more solute, the total number of moles increases, but the solvent moles do not. So the fraction that represents the solvent shrinks.

Mathematically, X_solvent = n_solvent / (n_solvent + n_solute). With n_solvent fixed and n_solute increasing, the denominator grows while the numerator stays the same, hence X_solvent decreases. For intuition, adding more solute increases the total particle count, making the solvent occupy a smaller share of the mixture.

So the solvent mole fraction decreases.

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